Determine the y-intercept of the following equation.left bracket, x, plus, 1, right bracket, left bracket, x, plus, 4, right bracket, equals, y(x+1)(x+4)=yAnswerMultiple Choice Answersleft bracket, 1, comma, 0, right bracket, and , left bracket, minus, 4, comma, 0, right bracket(1,0) and (−4,0)left bracket, 0, comma, 4, right bracket(0,4)left bracket, 0, comma, minus, 1, right bracket, and , left bracket, 0, comma, minus, 4, right bracket(0,−1) and (0,−4)left bracket, minus, 1, comma, 0, right bracket, and , left bracket, minus, 4, comma, 0, right bracket(−1,0) and (−4,0)left bracket, 4, comma, 0, right bracket(4,0)left bracket, 0, comma, minus, 4, right bracket(0,−4)
Question
Determine the y-intercept of the following equation.left bracket, x, plus, 1, right bracket, left bracket, x, plus, 4, right bracket, equals, y(x+1)(x+4)=yAnswerMultiple Choice Answersleft bracket, 1, comma, 0, right bracket, and , left bracket, minus, 4, comma, 0, right bracket(1,0) and (−4,0)left bracket, 0, comma, 4, right bracket(0,4)left bracket, 0, comma, minus, 1, right bracket, and , left bracket, 0, comma, minus, 4, right bracket(0,−1) and (0,−4)left bracket, minus, 1, comma, 0, right bracket, and , left bracket, minus, 4, comma, 0, right bracket(−1,0) and (−4,0)left bracket, 4, comma, 0, right bracket(4,0)left bracket, 0, comma, minus, 4, right bracket(0,−4)
Solution
The y-intercept of an equation is the point where the line crosses the y-axis. This is when x = 0.
So, to find the y-intercept of the equation y = (x+1)(x+4), we substitute x = 0 into the equation:
y = (0+1)(0+4) y = 1*4 y = 4
So, the y-intercept of the equation is (0,4).
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