At pH of 5, an acid has a dissociating constant of 1.0 X 10-4 and distribution coefficient of 100.Find the distribution ratio of this acid.
Question
At pH of 5, an acid has a dissociating constant of 1.0 X 10-4 and distribution coefficient of 100.Find the distribution ratio of this acid.
Solution
To find the distribution ratio (D) of the acid, we need to use the formula:
D = D' / (1 + Ka / [H+])
Where: D' is the distribution coefficient, Ka is the dissociation constant, and [H+] is the concentration of hydrogen ions.
Given: D' = 100, Ka = 1.0 x 10^-4, and pH = 5.
First, we need to convert the pH to [H+] using the formula:
[H+] = 10^-pH
So, [H+] = 10^-5 M.
Now, we can substitute these values into the formula for D:
D = 100 / (1 + 1.0 x 10^-4 / 10^-5)
Solving this gives:
D = 100 / (1 + 10)
D = 100 / 11
D = 9.09
So, the distribution ratio of the acid is approximately 9.09.
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