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Consider the following IEEE 754 32-bit floating point value:01001111 01001000 00000000 00000000Enter S, its sign, as either + or -. Enter E, its exponent part's value, in base 10.

Question

Consider the following IEEE 754 32-bit floating point value:01001111 01001000 00000000 00000000Enter S, its sign, as either + or -. Enter E, its exponent part's value, in base 10.

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Solution

The IEEE 754 32-bit floating point value is divided into three parts: the sign bit, the exponent, and the mantissa.

  1. Sign bit (S): The first bit is the sign bit. If the sign bit is 0, then the number is positive. If it's 1, the number is negative. In this case, the sign bit is 0, so S is +.

  2. Exponent (E): The next 8 bits are the exponent, expressed as a binary number. In this case, the exponent is 01001111, which is 79 in decimal. However, the IEEE 754 standard represents the exponent with a bias of 127, so we subtract 127 from the exponent to get the actual value. So, E is 79 - 127 = -48.

So, the sign S is + and the exponent E is -48.

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