(a) In the reaction Pb3O4 + 8HCl → 3PbCl2 + Cl2 + 4H2O, the oxidising agent is Pb3O4 because it gains electrons and is reduced to PbCl2.

(b) In the reaction 2Mg + O2 → 2MgO, the oxidising agent is O2 because it gains electrons and is reduced to MgO.

(c) In the reaction CuSO4 + Zn → Cu + ZnSO4, the oxidising agent is CuSO4 because it gains electrons and is reduced to Cu.

(d) In the reaction V2O5 + 5Ca → 2V + 5CaO, the oxidising agent is V2O5 because it gains electrons and is reduced to V.

(e) In the reaction 3Fe + 4H2O → Fe3O4 + 4H2, the oxidising agent is H2O because it gains electrons and is reduced to H2.

(f) In the reaction CuO + H2 → Cu + H2O, the oxidising agent is CuO because it gains electrons and is reduced to Cu.

Question

(a) In the reaction Pb3O4 + 8HCl → 3PbCl2 + Cl2 + 4H2O, the oxidising agent is Pb3O4 because it gains electrons and is reduced to PbCl2.

(b) In the reaction 2Mg + O2 → 2MgO, the oxidising agent is O2 because it gains electrons and is reduced to MgO.

(c) In the reaction CuSO4 + Zn → Cu + ZnSO4, the oxidising agent is CuSO4 because it gains electrons and is reduced to Cu.

(d) In the reaction V2O5 + 5Ca → 2V + 5CaO, the oxidising agent is V2O5 because it gains electrons and is reduced to V.

(e) In the reaction 3Fe + 4H2O → Fe3O4 + 4H2, the oxidising agent is H2O because it gains electrons and is reduced to H2.

(f) In the reaction CuO + H2 → Cu + H2O, the oxidising agent is CuO because it gains electrons and is reduced to Cu.

Knowee AI · Accepted Answer

(a) In the reaction Pb3O4 + 8HCl → 3PbCl2 + Cl2 + 4H2O, the oxidising agent is Pb3O4 because it gains electrons and is reduced to PbCl2.

(b) In the reaction 2Mg + O2 → 2MgO, the oxidising agent is O2 because it gains electrons and is reduced to MgO.

(c) In the reaction CuSO4 + Zn → Cu + ZnSO4, the oxidising agent is CuSO4 because it gains electrons and is reduced to Cu.

(d) In the reaction V2O5 + 5Ca → 2V + 5CaO, the oxidising agent is V2O5 because it gains electrons and is reduced to V.

(e) In the reaction 3Fe + 4H2O → Fe3O4 + 4H2, the oxidising agent is H2O because it gains electrons and is reduced to H2.

(f) In the reaction CuO + H2 → Cu + H2O, the oxidising agent is CuO because it gains electrons and is reduced to Cu.

Identify the oxidising agent (oxidant) in the following reactions(a) Pb3O4 + 8HCl → 3PbCl2 + Cl2 + 4H2O(b) 2Mg + O2 → 2MgO(c) CuSO4 + Zn → Cu + ZnSO4(d) V2O5 + 5Ca → 2V + 5CaO(e) 3Fe + 4H2O → Fe3O4 + 4H2(f) CuO + H2 → Cu + H2O