A charge per unit length λ = +5.26 μC/m is uniformly distributed along the positive y-axis from y = 0 to y = +a = +0.531 m. A charge per unit length λ = −5.26 μC/m is uniformly distributed along the negative y-axis from y = 0 to y = −a = −0.531 m. What is the magnitude of the electric field at a point on the x-axis a distance x = 0.291 m from the origin? (You may enter your calculation using scientific notation.) N/C
Question
A charge per unit length λ = +5.26 μC/m is uniformly distributed along the positive y-axis from y = 0 to y = +a = +0.531 m. A charge per unit length λ = −5.26 μC/m is uniformly distributed along the negative y-axis from y = 0 to y = −a = −0.531 m. What is the magnitude of the electric field at a point on the x-axis a distance x = 0.291 m from the origin? (You may enter your calculation using scientific notation.) N/C
Solution
The electric field E due to a line of charge is given by the formula:
E = λ / (2πε₀r)
where:
- λ is the linear charge density,
- ε₀ is the permittivity of free space (approximately 8.85 x 10^-12 C²/N·m²), and
- r is the distance from the line of charge.
In this case, we have two lines of charge, one positive and one negative, both a distance r = sqrt(a² + x²) from the point of interest. The electric field due to each line of charge will be equal in magnitude but opposite in direction, so they will add to give a net electric field of zero.
Therefore, the magnitude of the electric field at a point on the x-axis a distance x = 0.291 m from the origin is 0 N/C.
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