Metabolic acidosis is associated with decreased plasma level of(A) bicarbonate(B) lactate(C) oxygen(D) urea
Question
Metabolic acidosis is associated with decreased plasma level of(A) bicarbonate(B) lactate(C) oxygen(D) urea
Solution
Metabolic acidosis is a condition that occurs when the body produces excessive quantities of acid or when the kidneys are not removing enough acid from the body.
The primary indicator of metabolic acidosis is a decrease in plasma bicarbonate levels. Bicarbonate is a form of carbon dioxide (a weak acid), and it is used by the body to help maintain a stable blood pH. When the body is functioning normally, the kidneys help control bicarbonate levels. However, in metabolic acidosis, the kidneys are unable to effectively regulate bicarbonate levels, leading to a decrease in plasma bicarbonate.
Therefore, the correct answer is (A) bicarbonate.
Similar Questions
etabolic acidosis is associated with decreased plasma level of(A) bicarbonate(B) lactate(C) oxygen(D) urea
In renal compensation of acidosis:Question 50Select one:a.large amounts of bicarbonate ions are excreted in the urineb.the rate of hydrogen ion secretion is reducedc.the kidney reabsorbs filtered bicarbonate ions, and also contributes additional bicarbonate ions to the bloodd.the rate of bicarbonate secretion is reducede.the kidneys facilitate excretion of hydrogen ions, with no change to blood bicarbonate concentration
The kidneys will reabsorb more bicarbonate ions in response to acidosis.Question 36Select one:TrueFalse
What condition would an increase in bicarbonate ion lead to? A. acidosis B. diabetes mellitus C. alkalosis D. renal calculi
In metabolic alkalosis the compensation by the kidney shows1/1Normal bicarbonate and low carbon dioxideLow bicarbonate and normal carbon dioxideLow bicarbonate and high carbon dioxide High bicarbonate and high carbon dioxideHigh bicarbonate and low carbon dioxide
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.