Select the correct answerThe present ages of A, B and C are in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. What are their present ages (in years)?Options16, 28 4016, 30, 4016, 28, 3616, 28 , 45

Let's solve this step by step:

1. Let's assume the present ages of A, B, and C are 4x, 7x, and 9x respectively.

2. According to the problem, eight years ago, the sum of their ages was 56. So, we can write the equation as: (4x - 8) + (7x - 8) + (9x - 8) = 56

3. Simplifying the equation, we get: 20x - 24 = 56

4. Solving for x, we get: x = (56 + 24) / 20 = 4

5. So, the present ages of A, B, and C are: 4x = 16, 7x = 28, and 9x = 36 respectively.

Therefore, the correct answer is 16, 28, 36.

Let's solve this step by step:

Step 1: Let's assume the present ages of A, B, and C are 4x, 7x, and 9x respectively.

Step 2: According to the problem, eight years ago, the sum of their ages was 56. So, we can set up the equation: (4x - 8) + (7x - 8) + (9x - 8) = 56

Step 3: Simplifying the equation gives us: 20x - 24 = 56

Step 4: Solving for x, we get: x = (56 + 24) / 20 = 4

Step 5: Substituting x = 4 in 4x, 7x, and 9x, we get the present ages of A, B, and C as 16, 28, and 36 respectively.

So, the correct answer is 16, 28, 36.