A coolant solution is prepared using 250.0 mL of propylene glycol C3H8O2 with density 1.04g/cc, in 300.0 g of water. Calculate the new boiling point of the water. Note: Kb = 0.512degrees Celsius/molal
Question
A coolant solution is prepared using 250.0 mL of propylene glycol C3H8O2 with density 1.04g/cc, in 300.0 g of water. Calculate the new boiling point of the water. Note: Kb = 0.512degrees Celsius/molal
Solution
To calculate the new boiling point of the water, we need to use the formula for boiling point elevation. The formula is:
ΔTb = Kb * m
Where: ΔTb is the change in boiling point Kb is the molal boiling point elevation constant m is the molality of the solution
First, we need to calculate the molality of the solution. Molality is defined as the number of moles of solute per kilogram of solvent. In this case, the solute is propylene glycol and the solvent is water.
To calculate the molality, we need to find the number of moles of propylene glycol. We can use the formula:
moles = mass / molar mass
The molar mass of propylene glycol (C3H8O2) is 76.09 g/mol. So, the number of moles of propylene glycol is:
moles = 250.0 mL * 1.04 g/cc / 76.09 g/mol
Next, we need to convert the mass of water to kilograms:
mass of water = 300.0 g / 1000 = 0.300 kg
Now, we can calculate the molality:
molality = moles of propylene glycol / mass of water
Finally, we can calculate the change in boiling point:
ΔTb = Kb * molality
Substituting the values, we get:
ΔTb = 0.512 degrees Celsius/molal * molality
This will give us the change in boiling point. To find the new boiling point, we need to add this change to the normal boiling point of water, which is 100 degrees Celsius.
New boiling point = 100 degrees Celsius + ΔTb
By following these steps, you can calculate the new boiling point of the water in the coolant solution.
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