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How many times following loop will be executed?void main(){   int i = 32766;   while (i<= 32767)   {        printf("%d\n",i);         i = i + 1;     }}a.2 timesb.1 timesc.infinite timesd.loop will not be executed

Question

How many times following loop will be executed?void main(){   int i = 32766;   while (i<= 32767)   {        printf("%d\n",i);         i = i + 1;     }}a.2 timesb.1 timesc.infinite timesd.loop will not be executed

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Solution

To determine how many times the following loop will be executed, we need to analyze the code.

The loop condition is "while (i <= 32767)", which means the loop will continue executing as long as the value of "i" is less than or equal to 32767.

The initial value of "i" is 32766. Since 32766 is less than 32767, the loop will execute at least once.

Inside the loop, the value of "i" is incremented by 1 using the statement "i = i + 1".

Therefore, in each iteration of the loop, the value of "i" will increase by 1.

The loop will continue executing until the value of "i" becomes greater than 32767.

Since the maximum value of an integer in many programming languages is 32767, the loop will execute only once.

Therefore, the correct answer is b. 1 time.

This problem has been solved

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