The orbital hybridization of a central atom that has one lone pair and bonds to five other atoms is sp3d2.

Here's the step-by-step explanation:

1. Count the number of atoms bonded to the central atom (in this case, 5) and the number of lone pairs on the central atom (in this case, 1).

2. Add these two numbers together. In this case, 5 (atoms) + 1 (lone pair) = 6.

3. The sum corresponds to the type of hybridization: 2 corresponds to sp, 3 to sp2, 4 to sp3, 5 to sp3d, and 6 to sp3d2.

So, in this case, the hybridization is sp3d2.

Question

The orbital hybridization of a central atom that has one lone pair and bonds to five other atoms is sp3d2.

Here's the step-by-step explanation:

1. Count the number of atoms bonded to the central atom (in this case, 5) and the number of lone pairs on the central atom (in this case, 1).

2. Add these two numbers together. In this case, 5 (atoms) + 1 (lone pair) = 6.

3. The sum corresponds to the type of hybridization: 2 corresponds to sp, 3 to sp2, 4 to sp3, 5 to sp3d, and 6 to sp3d2.

So, in this case, the hybridization is sp3d2.

Knowee AI · Accepted Answer

The orbital hybridization of a central atom that has one lone pair and bonds to five other atoms is sp3d2.

Here's the step-by-step explanation:

1. Count the number of atoms bonded to the central atom (in this case, 5) and the number of lone pairs on the central atom (in this case, 1).

2. Add these two numbers together. In this case, 5 (atoms) + 1 (lone pair) = 6.

3. The sum corresponds to the type of hybridization: 2 corresponds to sp, 3 to sp2, 4 to sp3, 5 to sp3d, and 6 to sp3d2.

So, in this case, the hybridization is sp3d2.

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