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A sample of clean, dry air contains 0.0400% carbon dioxide by volume.(a) Calculate the number of molecules of carbon dioxide in 480 dm 3 of clean, dry air at roomtemperature and pressure.One mole of any gas contains 6.02 × 10 23 molecules

Question

A sample of clean, dry air contains 0.0400% carbon dioxide by volume.(a) Calculate the number of molecules of carbon dioxide in 480 dm 3 of clean, dry air at roomtemperature and pressure.One mole of any gas contains 6.02 × 10 23 molecules

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Solution

Step 1: Determine the volume of CO2 in the air sample

Given that the air sample contains 0.0400% carbon dioxide by volume, this means that in every 100 dm^3 of air, there is 0.0400 dm^3 of CO2.

So, in 480 dm^3 of air, the volume of CO2 would be (0.0400/100) * 480 = 0.192 dm^3.

Step 2: Convert the volume of CO2 to moles

At room temperature and pressure, 1 mole of any gas occupies 24 dm^3. Therefore, the number of moles of CO2 in 0.192 dm^3 would be 0.192/24 = 0.008 moles.

Step 3: Calculate the number of molecules of CO2

Given that 1 mole of any substance contains 6.02 × 10^23 molecules, the number of molecules in 0.008 moles of CO2 would be 0.008 * 6.02 × 10^23 = 4.816 × 10^22 molecules.

So, there are approximately 4.816 × 10^22 molecules of CO2 in 480 dm^3 of clean, dry air at room temperature and pressure.

This problem has been solved

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