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Bobby is putting bottles and cans in bags to take to a recycling facility. He puts bottles in bags of 8 and cans in bags of 20, with no partially filled bags. While counting up the cans and bottles, an employee at the recycling facility points out that Bobby has the same number of each. What is the smallest number of bottles that he can recycle?

Question

Bobby is putting bottles and cans in bags to take to a recycling facility. He puts bottles in bags of 8 and cans in bags of 20, with no partially filled bags. While counting up the cans and bottles, an employee at the recycling facility points out that Bobby has the same number of each. What is the smallest number of bottles that he can recycle?

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Solution

To solve this problem, we need to find the least common multiple (LCM) of the numbers 8 and 20, which represent the number of bottles and cans Bobby can put in each bag, respectively. The LCM of two numbers is the smallest number that is a multiple of both numbers.

Here are the steps to find the LCM of 8 and 20:

  1. Write down the prime factors of each number:

    • The prime factors of 8 are 2, 2, and 2.
    • The prime factors of 20 are 2, 2, and 5.
  2. Write down all the prime factors, without repetition, and the highest power of each factor when it appears in either number:

    • The prime factors are 2 and 5.
    • The highest power of 2 is 3 (because 8 = 2^3), and the highest power of 5 is 1 (because 20 = 2^2 * 5^1).
  3. Multiply these highest powers together:

    • The LCM is 2^3 * 5^1 = 8 * 5 = 40.

So, the smallest number of bottles that Bobby can recycle, such that he has the same number of bottles and cans, is 40.

This problem has been solved

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