The same 53 participants were also asked how many years that had worked in paid employment. Based on the sample data, a 95% confidence interval for underlying mean years of paid employment is (13.4, 17.4).A student tried using the confidence interval calculator to construct the confidence interval from the same sample data and got (14.4, 16.4) because they entered the wrong sample size.What sample size did they enter?

A human resource manager for a large company takes a random sample of 60 employees from the company database. Based on the sample she calculates a 95% confidence interval for the mean time of employment for all employees to be 8.7 to 15.2 years.Which of the following will provide a more informative (i.e., narrower) confidence interval than the 95% confidence interval? Check all that apply. Using a 90% confidence level (instead of 95%) Using a 99% confidence level (instead of 95%) Using a sample size of 40 employees (instead of 60) Using a sample size of 90 employees (instead of 60)

A group of statistics students decided to conduct a survey at their university to find the average (mean) amount of time students spent studying per week. Assuming a population standard deviation of twenty three hours, what is the required sample size if the error should be less than three hours with a 95% level of confidence?

You want to compute a 90% confidence interval for the mean of a population with unknown standard deviation. The sample size is 30. The correct distribution value for calculating the required confidence interval is:-Group of answer choices1.961.64491.6991.6971.311

A sample with a sample proportion of 0.4 and which of the following sizes will produce the widest 95% confidence interval when estimating the population parameter?A.55B.45C.35D.65SUBMITarrow_backPREVIOUS

A sample of size =n90 is drawn from a normal population whose standard deviation is =σ9.7. The sample mean is =x38.78.Part: 0 / 20 of 2 Parts CompletePart 1 of 2(a) Construct an 80% confidence interval for μ. Round the answer to at least two decimal places.An 80% confidence interval for the mean is <<μ.