Sure, here is the step by step solution:

Step 1: First, we need to calculate the amount of water produced by the combustion of hydrogen. We know that 1g of Hydrogen produces 9g of water. So, 6% of Hydrogen in the fuel will produce 6*9 = 54g of water.

Step 2: Next, we need to calculate the heat absorbed by this water. We know that the latent heat of steam is 587 cal/g. So, the heat absorbed by the water produced is 54g * 587 cal/g = 31698 cal.

Step 3: Now, we need to convert this heat absorbed from cal to kcal because the gross calorific value is given in kcal. So, 31698 cal = 31.698 kcal.

Step 4: Finally, we subtract the heat absorbed by the water from the gross calorific value to get the net calorific value. So, the net calorific value is 9804.6 kcal/kg - 31.698 kcal/kg = 9772.902 kcal/kg.

So, the net calorific value of the fuel is 9772.902 kcal/kg.

Question

Sure, here is the step by step solution:

Step 1: First, we need to calculate the amount of water produced by the combustion of hydrogen. We know that 1g of Hydrogen produces 9g of water. So, 6% of Hydrogen in the fuel will produce 6*9 = 54g of water.

Step 2: Next, we need to calculate the heat absorbed by this water. We know that the latent heat of steam is 587 cal/g. So, the heat absorbed by the water produced is 54g * 587 cal/g = 31698 cal.

Step 3: Now, we need to convert this heat absorbed from cal to kcal because the gross calorific value is given in kcal. So, 31698 cal = 31.698 kcal.

Step 4: Finally, we subtract the heat absorbed by the water from the gross calorific value to get the net calorific value. So, the net calorific value is 9804.6 kcal/kg - 31.698 kcal/kg = 9772.902 kcal/kg.

So, the net calorific value of the fuel is 9772.902 kcal/kg.

Knowee AI · Accepted Answer

Sure, here is the step by step solution:

Step 1: First, we need to calculate the amount of water produced by the combustion of hydrogen. We know that 1g of Hydrogen produces 9g of water. So, 6% of Hydrogen in the fuel will produce 6*9 = 54g of water.

Step 2: Next, we need to calculate the heat absorbed by this water. We know that the latent heat of steam is 587 cal/g. So, the heat absorbed by the water produced is 54g * 587 cal/g = 31698 cal.

Step 3: Now, we need to convert this heat absorbed from cal to kcal because the gross calorific value is given in kcal. So, 31698 cal = 31.698 kcal.

Step 4: Finally, we subtract the heat absorbed by the water from the gross calorific value to get the net calorific value. So, the net calorific value is 9804.6 kcal/kg - 31.698 kcal/kg = 9772.902 kcal/kg.

So, the net calorific value of the fuel is 9772.902 kcal/kg.

The gross calorific value of a fuel containing 6% H was found to be 9804.6 kcal/kg. Find the net calorific value if the latent heat of steam is 587 cal/g

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