Create the balanced chemical equation for the following reaction.aqueous gold (III) fluoride reacts with aqueous potassium phosphate*You must use subscripts where appropriate for full marks!!!
Question
Create the balanced chemical equation for the following reaction.aqueous gold (III) fluoride reacts with aqueous potassium phosphate*You must use subscripts where appropriate for full marks!!!
Solution
Sure, here is the balanced chemical equation for the reaction:
2 AuF3(aq) + 3 K3PO4(aq) -> Au2(PO4)3(s) + 9 KF(aq)
Explanation:
- Write the unbalanced equation: AuF3 + K3PO4 -> AuPO4 + KF
- Balance the equation for the gold (Au) atoms: 2 AuF3 + K3PO4 -> Au2(PO4)3 + KF
- Balance the equation for the phosphate (PO4) groups: 2 AuF3 + 3 K3PO4 -> Au2(PO4)3 + KF
- Balance the equation for the potassium (K) and fluorine (F) atoms: 2 AuF3 + 3 K3PO4 -> Au2(PO4)3 + 9 KF
So, the balanced chemical equation is: 2 AuF3(aq) + 3 K3PO4(aq) -> Au2(PO4)3(s) + 9 KF(aq)
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