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For each of the following parts, determine if overflow occurs (assume values are 6-bit fixed-point binary numbers):  0011.01+0100.10 does NOT overflow  1010.10+1101.01   0111.10+0000.11 DOES overflow  1010.10+1110.00 DOES overflow  1110.10+0001.10

Question

For each of the following parts, determine if overflow occurs (assume values are 6-bit fixed-point binary numbers):  0011.01+0100.10 does NOT overflow  1010.10+1101.01   0111.10+0000.11 DOES overflow  1010.10+1110.00 DOES overflow  1110.10+0001.10

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Solution

Sure, let's go through each of these step by step:

  1. 0011.01 + 0100.10: In decimal, these numbers are 3.25 and 4.5 respectively. Their sum is 7.75, which can be represented as 0111.11 in 6-bit fixed-point binary. Therefore, overflow does not occur.

  2. 1010.10 + 1101.01:

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n this challenge, you will use logical bitwise operators. All data is stored in its binary representation. The logical operators, and C language, use to represent true and to represent false. The logical operators compare bits in two numbers and return true or false, or , for each bit compared.Bitwise AND operator & The output of bitwise AND is 1 if the corresponding bits of two operands is 1. If either bit of an operand is 0, the result of corresponding bit is evaluated to 0. It is denoted by &.Bitwise OR operator | The output of bitwise OR is 1 if at least one corresponding bit of two operands is 1. It is denoted by |.Bitwise XOR (exclusive OR) operator ^ The result of bitwise XOR operator is 1 if the corresponding bits of two operands are opposite. It is denoted by .For example, for integers 3 and 5,3 = 00000011 (In Binary)5 = 00000101 (In Binary)AND operation OR operation XOR operation 00000011 00000011 00000011& 00000101 | 00000101 ^ 00000101 ________ ________ ________ 00000001 = 1 00000111 = 7 00000110 = 6You will be given an integer , and a threshold, i1nnik$. Print the results of the and, or and exclusive or comparisons on separate lines, in that order.ExampleThe results of the comparisons are below:a b and or xor1 2 0 3 31 3 1 3 22 3 2 3 1For the and comparison, the maximum is . For the or comparison, none of the values is less than , so the maximum is . For the xor comparison, the maximum value less than is . The function should print:202Function DescriptionComplete the calculate_the_maximum function in the editor below.calculate_the_maximum has the following parameters:int n: the highest number to considerint k: the result of a comparison must be lower than this number to be consideredPrintsPrint the maximum values for the and, or and xor comparisons, each on a separate line.Input FormatThe only line contains space-separated integers, and .ConstraintsSample Input 05 4Sample Output 0233Explanation 0All possible values of and are:The maximum possible value of that is also is , so we print on first line.The maximum possible value of that is also is , so we print on second line.The maximum possible value of that is also is , so we print on third line.

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