The product of two consecutive natural numbers is 56. Find the numbers.

Let's denote the two consecutive natural numbers as n and n+1.

According to the problem, the product of these two numbers is 56. So, we can write the equation as:

n*(n+1) = 56

This is a quadratic equation, which we can solve to find the value of n.

First, expand the equation:

n^2 + n = 56

Rearrange the equation to set it equal to zero:

n^2 + n - 56 = 0

Now, we can factor the equation:

(n - 7)(n + 8) = 0

Setting each factor equal to zero gives the solutions n = 7 and n = -8.

Since we're looking for natural numbers, we discard the negative solution. So, n = 7 is the only solution.

Therefore, the two consecutive natural numbers are 7 and 8.