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The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. The upper class limit of the highest class isa.15b.40c.25d.35

Question

The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. The upper class limit of the highest class isa.15b.40c.25d.35

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Solution

The upper class limit of the highest class can be calculated by adding the width of the classes to the lower limit of the lowest class, multiplied by the number of classes.

Here's how to do it:

  1. Identify the width of each class: 5
  2. Identify the lower class limit of the lowest class: 10
  3. Identify the number of classes: 5

Now, calculate the upper class limit of the highest class:

  1. Multiply the width of each class by the number of classes: 5 * 5 = 25
  2. Add the result to the lower class limit of the lowest class: 25 + 10 = 35

So, the upper class limit of the highest class is 35. Therefore, the correct answer is d.35.

This problem has been solved

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