Sydney has five pink socks, six yellow socks and four red socks in her drawer.What is the probability that she'll randomly pick a yellow sock, put it on, thenrandomly pick a pink sock?
Question
Sydney has five pink socks, six yellow socks and four red socks in her drawer.What is the probability that she'll randomly pick a yellow sock, put it on, thenrandomly pick a pink sock?
Solution
Step 1: Calculate the total number of socks. Sydney has 5 pink socks, 6 yellow socks, and 4 red socks. So, the total number of socks is 5 + 6 + 4 = 15 socks.
Step 2: Calculate the probability of picking a yellow sock first. The probability of an event is calculated by dividing the number of favorable outcomes by the total number of outcomes. In this case, the favorable outcome is picking a yellow sock, and there are 6 yellow socks. So, the probability of picking a yellow sock first is 6/15 = 0.4.
Step 3: After picking a yellow sock, Sydney puts it on and doesn't put it back in the drawer. So, the total number of socks in the drawer is now 14.
Step 4: Calculate the probability of picking a pink sock next. There are 5 pink socks, so the probability is 5/14 = 0.357.
Step 5: The final step is to calculate the probability of both events happening. In probability, the "and" operation is represented by multiplication. So, the probability that she'll randomly pick a yellow sock and then a pink sock is 0.4 * 0.357 = 0.143.
So, the probability that Sydney will pick a yellow sock first and then a pink sock is approximately 0.143 or 14.3%.
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