Ammonium chromate, (NH4)2CrO4NH42CrO4 , contains what percent nitrogen by mass? 36.8%36.8% 32.0%32.0% 9.21%9.21% 18.4%18.4% 11.9%11.9%

To find the percent of nitrogen by mass in Ammonium chromate, (NH4)2CrO4, you need to follow these steps:

1. Find the molar mass of each element in the compound and the molar mass of the compound itself.

   • Nitrogen (N): 14.01 g/mol
   • Hydrogen (H): 1.01 g/mol
   • Chromium (Cr): 52.00 g/mol
   • Oxygen (O): 16.00 g/mol

2. Calculate the molar mass of the compound.

   • There are 2 nitrogen atoms, 8 hydrogen atoms, 1 chromium atom, and 4 oxygen atoms in the compound.
   • (2 * 14.01 g/mol) + (8 * 1.01 g/mol) + (52.00 g/mol) + (4 * 16.00 g/mol) = 28.02 g/mol + 8.08 g/mol + 52.00 g/mol + 64.00 g/mol = 152.10 g/mol

3. Calculate the percent of nitrogen by mass.

   • The formula for percent composition is: (mass of element/molar mass of compound) * 100%
   • (28.02 g/mol / 152.10 g/mol) * 100% = 18.4%

So, the percent of nitrogen by mass in Ammonium chromate is 18.4%.