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What would be the output of the following code?import java.util.LinkedList;import java.util.Queue;import java.util.Stack;class Test { public static void main (String[] args) { Queue<Integer> q=new LinkedList<Integer>(); Stack<Integer> s=new Stack<Integer>(); q.add(5); q.add(10); s.push(10); s.push(20); System.out.print(q.peek()+s.pop()); }}

Question

What would be the output of the following code?import java.util.LinkedList;import java.util.Queue;import java.util.Stack;class Test { public static void main (String[] args) { Queue<Integer> q=new LinkedList<Integer>(); Stack<Integer> s=new Stack<Integer>(); q.add(5); q.add(10); s.push(10); s.push(20); System.out.print(q.peek()+s.pop()); }}

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Solution

The output of the code would be 25.

Here's the step by step explanation:

  1. A Queue (q) and a Stack (s) of Integer type are created.
  2. The numbers 5 and 10 are added to the queue. The queue now looks like this: [5, 10].
  3. The numbers 10 and 20 are pushed onto the stack. The stack now looks like this: [10, 20].
  4. The peek() method is called on the queue, which retrieves, but does not remove, the head of this queue. In this case, it returns 5.
  5. The pop() method is called on the stack, which removes the object at the top of this stack and returns that object as the value of this function. In this case, it returns 20.
  6. The values retrieved from the queue and stack (5 and 20) are added together, resulting in 25.
  7. The System.out.print() function prints the result, which is 25.

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