What will be the result of following Python code snippet after execution?a=0b=1if (a and b): print("hi")elif(not(a)): print("hello")elif(b): print("hi world")else: print("hello world")
Question
What will be the result of following Python code snippet after execution?a=0b=1if (a and b): print("hi")elif(not(a)): print("hello")elif(b): print("hi world")else: print("hello world")
Solution
The Python code snippet you provided will print "hello" after execution. Here's the step-by-step explanation:
- The variables
aandbare assigned the values 0 and 1 respectively. - The
ifstatement checks if bothaandbare true. In Python, 0 is consideredFalseand 1 is consideredTrue. Sinceais 0 (orFalse), the conditiona and bisFalse. Therefore, the code inside theifblock is skipped. - The
elifstatement checks ifnot(a)is true. Sinceais 0,not(a)isTrue. Therefore, the code inside thiselifblock is executed, which isprint("hello"). - After executing the
elifblock, the program doesn't check the remainingeliforelseblocks. Therefore, "hello" is the only output of this code.
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