An e.m.f. of 16 volts is induced in a coil of inductance 4H. The rate of change of current must be:a.32 A/sb.16 A/sc.64 A/sd.4 A/s
Question
An e.m.f. of 16 volts is induced in a coil of inductance 4H. The rate of change of current must be:a.32 A/sb.16 A/sc.64 A/sd.4 A/s
Solution
The electromotive force (emf) induced in a coil is given by the formula:
emf = L * (dI/dt)
where: L is the inductance of the coil, dI/dt is the rate of change of current.
Rearranging for dI/dt gives:
dI/dt = emf / L
Given: emf = 16 V, L = 4 H.
Substituting these values into the formula, we get:
dI/dt = 16 V / 4 H dI/dt = 4 A/s
So, the rate of change of current must be 4 A/s. Therefore, the correct answer is d. 4 A/s.
Similar Questions
The current in a coil decreases from 30 amp to 10 amp in 0.2 sec if the self inductance of coil is 4 Henry. What is the induced emf in volts?
An inductor has inductance of 0.280 HH and carries a current that is decreasing at a uniform rate of 15.0 mA/smA/s .Part AFind the self-induced emf in this inductor.Express your answer in millivolts.
The current in a coil changes from 2 A to 10 A in 80 ms. As a result, an e.m.f of 5.0V is induced in the coil. Determine the magnitude of the self-inductance of the coil
The current in a coil of inductance 5H decreases at the rate of 2A/s. The induced e.m.f is
A coil induces 350 mV when the current changes at the rate of 1 A/s. The value of inductance is:a.350mHb.250mHc.150mHd.3,500mH
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.