Given 2 rectangles parallel to coordinate axes, find the area covered by them.Input FormatThe first line of input contains T - the number of test cases. It is followed by 2T lines. The first line of each test case contains 4 integers - xbl, ybl, xtr, ytr - the bottom-left and top-right coordinates of rectangle-1. The second line of each test case contains 4 integers - xbl, ybl, xtr, ytr - the bottom-left and top-right coordinates of rectangle-2.Output FormatFor each test case, print the area covered by the 2 rectangles, separated by a newline.Constraints1 <= T <= 10000-106 < x,y <= 106(xbl, ybl) < (xtr, ytr)ExampleInput42 5 4 61 2 5 4-4 -3 -2 5-3 -5 1 31 0 3 52 3 5 8-2 2 4 4-3 1 5 5Output10422332

The problem is asking to calculate the total area covered by two rectangles. The rectangles are parallel to the coordinate axes. The input is the coordinates of the bottom-left and top-right corners of each rectangle.

Here are the steps to solve this problem:

1. First, calculate the area of each rectangle. The area of a rectangle is given by the formula width * height. Since the rectangles are parallel to the coordinate axes, the width is the difference between the x-coordinates and the height is the difference between the y-coordinates. So, for each rectangle, calculate the area as (xtr - xbl) * (ytr - ybl).

2. Next, check if the rectangles overlap. If they do, you need to subtract the area of the overlap from the total area. To check if the rectangles overlap, compare the coordinates of the corners. If the bottom-left corner of one rectangle is to the right of the top-right corner of the other, or above it, then the rectangles do not overlap. Similarly, if the top-right corner of one rectangle is to the left of the bottom-left corner of the other, or below it, then the rectangles do not overlap.

3. If the rectangles overlap, calculate the