Which of the following V-I curve is belongs to Ohmic components Straight line V-I curve Non-linear V-I curve Parabolic VI curve Sinusoidal VI curve
Question
Which of the following V-I curve is belongs to Ohmic components Straight line V-I curve Non-linear V-I curve Parabolic VI curve Sinusoidal VI curve
Solution
The V-I curve that belongs to Ohmic components is the Straight line V-I curve.
Here's why:
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Ohm's Law states that the current through a conductor between two points is directly proportional to the voltage across the two points. This means that if you were to increase the voltage, the current would increase proportionally, and vice versa.
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This relationship is represented graphically as a straight line on a Voltage-Current (V-I) graph. The slope of this line represents the resistance of the component.
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Non-linear, parabolic, and sinusoidal V-I curves represent non-ohmic components, where the current does not change proportionally with the voltage. These could be components like diodes, transistors, or other semiconductor devices.
So, the straight line V-I curve is the one that belongs to Ohmic components.
Similar Questions
For the bulb, the plot of V vs I (with voltage on the y axis and current on the x axis) looks like:
Students are provided with an unknown resistor that has a constant resistance for all potential differences. The students are instructed to plot an I-V graph for the resistor.Which, if any, of the following are true for I-V graphs of ohmic devices?Amust be a horizontal lineBmust pass through the originCmust not pass through the originDnone of the above
For the resistor, the plot of V vs I (with voltage on the y axis and current on the x axis) looks like:
The slope of the V-I curve at low current densities represents the cell's internal resistance or ohmic losses.A steeper slope indicates higher resistance, leading to lower voltage output for a given current density.
Slope of I-V graph of a resistor is numerically equal to:
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