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A system of equations has 1 solution. If 4x−y=5 is one of the equations, which could be the other equation?Responsesy=−4x+5y is equal to negative 4 x plus 52y=8x−102 y is equal to 8 x minus 10y=4x−5y is equal to 4 x minus 5−2y=−8x−10

Question

A system of equations has 1 solution. If 4x−y=5 is one of the equations, which could be the other equation?Responsesy=−4x+5y is equal to negative 4 x plus 52y=8x−102 y is equal to 8 x minus 10y=4x−5y is equal to 4 x minus 5−2y=−8x−10

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Solution

The other equation could be 2y=8x−10.

Here's why:

The given equation is 4x - y = 5. We can rearrange this to y = 4x - 5.

Now, let's look at the second equation, 2y = 8x - 10. We can rearrange this to y = 4x - 5.

Since both equations are the same, they will intersect at all points, meaning there is only one solution to this system of equations.

The other options won't work because:

  • y = -4x + 5: This line has a different slope and y-intercept, so it will intersect the given line at one point, but it will not coincide with it.
  • y = 4x - 5: This is the same as the given equation, so it's not a different equation.
  • -2y = -8x - 10: This can be simplified to y = 4x + 5, which is a different line from the given equation.

This problem has been solved

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