Given a number N, find the least palindromic number K, such that K>N.Input FormatFirst line of input contains T - number of test cases. Its followed by T lines, each contains a single number N.Constraints30 points1 <= T <= 1041 <= N <= 10470 points1 <= T <= 1051 <= N <= 109Output FormatFor each test case, print the least palindromic number K, such that K>N, separated by newline.Sample Input 0211121Sample Output 022131

To solve this problem, we need to find the least palindromic number K that is greater than the given number N. We will follow the steps below:

1. Read the number of test cases, T.
2. Iterate T times to process each test case.
3. For each test case, read the number N.
4. Increment N by 1 to find the next number.
5. Convert the incremented number to a string.
6. Check if the string is already a palindrome. If it is, increment the number by 1 and convert it to a string again.
7. Repeat step 6 until we find a palindrome.
8. Print the least palindromic number K.

Let's implement this algorithm in code.

To solve this problem, we need to find the least palindromic number K that is greater than the given number N. We will follow the steps below:

1. Read the number of test cases, T.
2. Iterate T times to process each test case.
3. For each test case, read the number N.
4. Increment N by 1 to find the next number.
5. Convert the incremented number to a string.
6. Check if the string is already a palindrome.
7. If it is not a palindrome, find the middle index of the string.
8. Iterate from the middle index towards the left and right, comparing the characters.
9. If the characters are not equal, replace the character on the right side with the character on the left side.
10. If the characters are equal, continue iterating towards the left and right until a mismatch is found or the indices go out of bounds.
11. Convert the modified string back to an integer.
12. Print the least palindromic number K.

Here is the implementation in Python:

def is_palindrome(s):
    return s == s[::-1]

def find_least_palindromic_number(n):
    n += 1
    s = str(n)
    if not is_palindrome(s):
        mid = len(s) // 2
        i = mid - 1
        j = mid + 1 if len(s) % 2 != 0 else mid
        while i >= 0 and j < len(s):
            if s[i] != s[j]:
                s = s[:j] + s[i] + s[j+1:]
            i -= 1
            j += 1
    return int(s)

# Read the number of test cases
t = int(input())

# Process each test case
for _ in range(t):
    # Read the number N
    n = int(input())
    
    # Find the least palindromic number K
    k = find_least_palindromic_number(n)
    
    # Print the result
    print(k)

This code will take the number of test cases as input, followed by the test cases themselves. It will then find the least palindromic number K for each test case and print the result.