A chemist prepares a solution of calcium sulfate CaSO4 by measuring out 6.16mg of calcium sulfate into a 200.mL volumetric flask and filling the flask to the mark with water.Calculate the concentration in /molL of the chemist's calcium sulfate solution. Be sure your answer has the correct number of significant digits.

Sure, here are the steps to calculate the concentration of the calcium sulfate solution:

1. First, we need to convert the mass of calcium sulfate from milligrams to grams because the molar mass is usually in grams per mole. So, 6.16 mg is equal to 0.00616 g.

2. Next, we need to calculate the molar mass of calcium sulfate (CaSO4). The molar mass of Ca is approximately 40.08 g/mol, S is approximately 32.06 g/mol, and O is approximately 16.00 g/mol. Since there are four oxygen atoms in CaSO4, we multiply the molar mass of O by 4. So, the molar mass of CaSO4 is 40.08 g/mol + 32.06 g/mol + 4(16.00 g/mol) = 136.14 g/mol.

3. Now, we can calculate the number of moles of CaSO4 by dividing the mass of CaSO4 by its molar mass. So, 0.00616 g ÷ 136.14 g/mol = 4.52 x 10^-5 mol.

4. The concentration of a solution is defined as the amount of solute (in moles) divided by the volume of the solution (in liters). The volume of the solution is 200 mL, which is equal to 0.2 L. So, the concentration of the solution is 4.52 x 10^-5 mol ÷ 0.2 L = 2.26 x 10^-4 mol/L.

So, the concentration of the chemist's calcium sulfate solution is 2.26 x 10^-4 mol/L.