Last year three examiners spent six hours marking exam papers.This year the same process took only three hours.How many examiners were there this time if they marked the same set of papers at the same rate?
Question
Last year three examiners spent six hours marking exam papers.This year the same process took only three hours.How many examiners were there this time if they marked the same set of papers at the same rate?
Solution
To solve this problem, we need to understand that the time taken to mark the papers is inversely proportional to the number of examiners. This means that if the number of examiners doubles, the time taken to mark the papers will be halved.
Step 1: Identify the initial conditions. Last year, there were 3 examiners and they took 6 hours to mark the papers.
Step 2: Identify the final conditions. This year, the time taken to mark the papers was halved to 3 hours.
Step 3: Since the time taken was halved, this means that the number of examiners must have doubled (because time and number of examiners are inversely proportional).
Step 4: Therefore, this year there were 3 examiners * 2 = 6 examiners.
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