Reverse last k digits of the given numberInput Format:Accept two integer as inputOutput Format:print the reversed k digits
Question
Reverse last k digits of the given numberInput Format:Accept two integer as inputOutput Format:print the reversed k digits
Solution
Here is a step-by-step solution in Python:
- First, we need to accept two integers as input. Let's call the first integer
numand the second integerk.
num = int(input("Enter the number: "))
k = int(input("Enter the number of digits to reverse: "))
- Next, we need to extract the last
kdigits fromnum. We can do this by convertingnumto a string, slicing the lastkcharacters, and then converting back to an integer.
last_k_digits = int(str(num)[-k:])
- Now, we need to reverse these
kdigits. We can do this by convertinglast_k_digitsto a string, reversing the string using slicing, and then converting back to an integer.
reversed_digits = int(str(last_k_digits)[::-1])
- Finally, we need to replace the last
kdigits ofnumwithreversed_digits. We can do this by subtractinglast_k_digitsfromnum, and then addingreversed_digits.
num = num - last_k_digits
num = num + reversed_digits
- Print the final result.
print("The number after reversing the last k digits is: ", num)
Please note that this solution assumes that num has at least k digits. If num has fewer than k digits, the program will reverse all the digits of num.
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