A dishonest milkman professes to sell his milk at cost price but he mixes it with water and thereby gains 25%. The percentage of water in the mixture is?
Question
A dishonest milkman professes to sell his milk at cost price but he mixes it with water and thereby gains 25%. The percentage of water in the mixture is?
Solution
Let's solve this step by step:
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Assume the cost price of 1 litre milk is $1.
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As the milkman gains 25%, he actually uses only 0.75 litre of milk and sells it as 1 litre (because he says he is selling at cost price, but he is actually gaining 25%).
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The remaining 0.25 litre is water (since he sells 1 litre of mixture which includes milk and water).
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Therefore, the percentage of water in the mixture is (0.25/1)*100 = 25%.
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