A solid sphere of radius  R gravitationally attracts a particle placed at  3R  from its centre with a force  F1. Now a spherical cavity of radius  (R2) is made in the sphere (as shown in figure) and the force becomes  F2. The value of  F1  :  F2  is:

Two lead spheres of same radius are in contact with each other. The gravitational force of attraction between them is F. If two lead spheres of double the previous radius are in contact with each other, the gravitational force of attraction between them will be:

force between two identical spheres charged with same charge is F. If 50% charge of one sphere is transferred to the other sphere then the new force will be:

The radius, R, of a sphere is 6.6mm. Calculate the sphere's volume, V.Use the value 3.14 for π, and round your answer to the nearest tenth. (Do not round any intermediate computations.)=Vmm3

7) Calculate the volume of the sphere, both in terms of p & to the nearest tenth, in which r= 3 in

The radius, R, of a sphere is 3.2cm. Calculate the sphere's volume, V.Use the value 3.14 for π, and round your answer to the nearest tenth. (Do not round any intermediate computations.)=Vcm3