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A Boy walks 12kms towards east. He turns 90° clockwise and walks 20kms then he turned right and walked for 33kms. How far is he from starting point?Question 20Answera.29b.30c.27d.28

Question

A Boy walks 12kms towards east. He turns 90° clockwise and walks 20kms then he turned right and walked for 33kms. How far is he from starting point?Question 20Answera.29b.30c.27d.28

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Solution

The boy's movements can be represented on a coordinate plane.

  1. He starts at the origin (0,0) and walks 12 kms east. His position is now (12,0).
  2. He turns 90 degrees clockwise (which is a turn to the south in this context) and walks 20 kms. His position is now (12,-20).
  3. He turns right from his current direction (which is a turn to the west in this context) and walks 33 kms. His position is now (-21,-20).

The boy's distance from the starting point can be calculated using the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

In this case, the boy's horizontal distance from the starting point is 21 kms (the absolute value of -21) and his vertical distance from the starting point is 20 kms.

So, the boy's total distance from the starting point is sqrt((21^2) + (20^2)) = sqrt(441 + 400) = sqrt(841) = 29 kms.

So, the answer is a. 29 kms.

This problem has been solved

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