If the sum of four consecutive odd numbers is 64, what is the largest of these numbers?

Let's denote the four consecutive odd numbers as x, x+2, x+4, and x+6. These are four consecutive odd numbers because odd numbers always differ by 2.

According to the problem, the sum of these four numbers is 64. So we can write the equation:

x + (x+2) + (x+4) + (x+6) = 64

Solving this equation will give us the value of x:

4x + 12 = 64 4x = 64 - 12 4x = 52 x = 52 / 4 x = 13

So, the smallest of the four numbers is 13. The largest number would be x+6, which is 13+6 = 19.

Therefore, the largest of these four consecutive odd numbers is 19.

Let's denote the four consecutive odd numbers as x, x+2, x+4, and x+6. These are four consecutive odd numbers because odd numbers always differ by 2.

According to the problem, the sum of these four numbers is 64. So we can write the equation:

x + (x+2) + (x+4) + (x+6) = 64

Solving this equation will give us the value of x, which is the smallest of the four numbers. Then we can find the largest number by adding 6 to x.

Let's solve the equation:

4x + 12 = 64 4x = 64 - 12 4x = 52 x = 52 / 4 x = 13

So, the smallest of the four numbers is 13. The largest number is therefore 13 + 6 = 19.