Assuming that all variables are non-zero, simplify $$(4z2y0x4​)−2 using positive indices.

The expression you provided seems to have a typo. It's not clear what the operation is between the variables. However, if you meant to simplify the expression $(4z^2y^0x^4)^{-2}$ using positive indices, here are the steps:

1. First, remember that any number or variable raised to the power of 0 is 1. So, $y^0$ becomes 1.

2. The expression then becomes $(4z^2*1*x^4)^{-2}$, which simplifies to $(4z^2x^4)^{-2}$.

3. Next, remember that a negative exponent means to take the reciprocal of the base. So, $(4z^2x^4)^{-2}$ becomes $\frac{1}{(4z^2x^4)^2}$.

4. Then, square each part inside the parentheses. $4^2$ is 16, $(z^2)^2$ is $z^4$, and $(x^4)^2$ is $x^8$.

5. So, the expression becomes $\frac{1}{16z^4x^8}$.

Therefore, the simplified form of $(4z^2y^0x^4)^{-2}$ using positive indices is $\frac{1}{16z^4x^8}$.