Use implicit differentiation to find 𝒅𝒚𝒅𝒙 if a) 5y2+siny= lnx2 b) 5y3-tany=ln2x-2x2In Problem (12-16), Finda) interval on which f is increasingb) interval on which f is decreasingc) open interval on which f is concave upd) open interval on which f is concave downe) the x-Coordinates of all infection pointsf) critical points
Question
Use implicit differentiation to find 𝒅𝒚𝒅𝒙 if a) 5y2+siny= lnx2 b) 5y3-tany=ln2x-2x2In Problem (12-16), Finda) interval on which f is increasingb) interval on which f is decreasingc) open interval on which f is concave upd) open interval on which f is concave downe) the x-Coordinates of all infection pointsf) critical points
Solution
It seems like you've asked multiple questions in one go. Let's break it down:
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Use implicit differentiation to find 𝒅𝒚/𝒅𝒙 if a) 5y²+sin(y)= ln(x²) b) 5y³-tan(y)=ln(2x)-2x²
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In Problem (12-16), Find a) interval on which f is increasing b) interval on which f is decreasing c) open interval on which f is concave up d) open interval on which f is concave down e) the x-Coordinates of all infection points f) critical points
Let's start with the first part:
a) 5y²+sin(y)= ln(x²)
Differentiating both sides with respect to x, we get:
10y(dy/dx) + cos(y)(dy/dx) = 2x/x² Solving for dy/dx, we get:
dy/dx = 2x/(10y + cos(y)x²)
b) 5y³-tan(y)=ln(2x)-2x²
Differentiating both sides with respect to x, we get:
15y²(dy/dx) - sec²(y)(dy/dx) = 2/x - 4x Solving for dy/dx, we get:
dy/dx = (2/x - 4x)/(15y² - sec²(y))
For the second part of your question, you didn't provide a specific function f(x) to analyze. Please provide the function so I can help you find the intervals of increase/decrease, concavity, inflection points, and critical points.
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Use implicit differentiation to find 𝒅𝒚𝒅𝒙 if a) 5y2+siny= lnx2 b) 5y3-tany=ln2x-2x2
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