What is the energy of one photon of light emittedfrom a TV remote controller that make use ofgreen light with a wavelength of 507 nm?
Question
What is the energy of one photon of light emittedfrom a TV remote controller that make use ofgreen light with a wavelength of 507 nm?
Solution
Sure, to calculate the energy of a photon, we can use the formula:
E = hc/λ
where: E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 Joule seconds), c is the speed of light (3.00 x 10^8 meters/second), and λ is the wavelength of the light.
In this case, the wavelength is given in nanometers (nm), but we need it in meters (m) for the units to work out. So first, convert the wavelength from nm to m:
507 nm = 507 x 10^-9 m = 5.07 x 10^-7 m
Now, plug the values into the formula:
E = (6.626 x 10^-34 J*s) * (3.00 x 10^8 m/s) / (5.07 x 10^-7 m)
Solving this gives:
E = 3.92 x 10^-19 Joules
So, the energy of one photon of green light emitted from a TV remote controller is approximately 3.92 x 10^-19 Joules.
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