A diver of mass 83.2 kg enters the water at a velocity of -1,2,3, if it takes 1.8 sec to reach zero velocity after hitting the water. What is the average net ( force on the diver during this time ? )
Question
A diver of mass 83.2 kg enters the water at a velocity of -1,2,3, if it takes 1.8 sec to reach zero velocity after hitting the water. What is the average net ( force on the diver during this time ? )
Solution
The problem seems to be a bit unclear, but I'll assume that the diver's velocity is a vector with components -1 m/s, 2 m/s, and 3 m/s. The magnitude of this velocity vector can be found using the Pythagorean theorem:
v = sqrt((-1)^2 + 2^2 + 3^2) = sqrt(14) m/s
The diver comes to a stop, so the final velocity is 0 m/s. The change in velocity (Δv) is then:
Δv = v_final - v_initial = 0 - sqrt(14) = -sqrt(14) m/s
The time it takes for this change in velocity is given as 1.8 seconds. So, the average acceleration (a) can be found using the formula:
a = Δv / Δt = -sqrt(14) / 1.8 m/s²
Finally, we can find the average net force (F) using Newton's second law, F = ma:
F = m * a = 83.2 kg * (-sqrt(14) / 1.8 m/s²)
This will give you the average net force on the diver during this time.
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