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A saturated solution of Ca3(PO4)2 has[Ca2+] = 2 × 10–8 M and  = 1.6 × 10–5 M Ksp of Ca3(PO4)2 is :-3.2 × 10–133.2 × 10–342.048 × 10–333.2 × 10–15

Question

A saturated solution of Ca3(PO4)2 has[Ca2+] = 2 × 10–8 M and  = 1.6 × 10–5 M Ksp of Ca3(PO4)2 is :-3.2 × 10–133.2 × 10–342.048 × 10–333.2 × 10–15

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Solution

The solubility product constant, Ksp, can be calculated using the concentrations of the ions in a saturated solution. The formula for calcium phosphate is Ca3(PO4)2, which means that in a saturated solution, one formula unit dissociates into 3 Ca2+ ions and 2 PO43- ions.

The Ksp expression for Ca3(PO4)2 is:

Ksp = [Ca2+]^3 * [PO4^3-]^2

Given that [Ca2+] = 2 × 10–8 M and [PO4^3-] = 1.6 × 10–5 M, we can substitute these values into the Ksp expression:

Ksp = (2 × 10–8)^3 * (1.6 × 10–5)^2

= 8 × 10–24 * 2.56 × 10–10

= 2.048 × 10–33

So, the Ksp of Ca3(PO4)2 is 2.048 × 10–33.

This problem has been solved

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