The equation below can be used to find the specific heat capacity of a substance. Work out the specific heat capacity of a substance if it takes 5,200J of energy to heat 2kg of it from 42°C to 47°C.

The specific heat capacity of a pure substance can be found by dividing the heat needed to change the temperature of a sample of the substance by the mass of the sample and by the change in temperature. The heat capacity of a certain substance has been measured to be 1.50J·g°C. Suppose 203.g of the substance are heated until the temperature of the sample has changed by 27.2°C.Write an equation that will let you calculate the heat Q that was needed for this temperature change. Your equation should contain only symbols. Be sure you define each symbol.

Specific heat capacity

When 860J of heat energy is supplied to a 0.4kg of a substance, its temperature rises from 250C to 500C. What is the specific heat capacity of this substance?Question 24Answera.120J/kg kb.172 J/kg kc.86J/kg kd.43J/kg k

What is meant by the specific heat capacity of a material?The amount of energy which is required to change 1 kilogram of the material from a liquid to a gasThe total amount of thermal energy which can be stored by 1 kilogram of the materialThe amount of energy required to raise the temperature of 1 kilogram of the material by 1 degree CelsiusThe amount of energy which is required to change 1 kilogram of the material from a solid to a liquid2The specific heat capacity of water is 4200 J/kg °C.  Calculate the amount of energy required to raise the temperature of 500 g of water from 20 to 70 °C.105 kJ105 MJ (105,000,000 J)147 kJ147 MJ (147,000,000 J)3A heater is used to transfer 40 kJ of energy to the thermal store of a 2 kg copper cylinder.  By how much will this cause the temperature of the copper to increase?  The specific heat capacity of copper is 385 J/kg °C.0.05 °C207.8 °C51.9 °C0.21 °C41,300 J of energy is transferred to the thermal store of a block of gold of mass 0.2 kg.  This causes its temperature to rise from 100 to 150 °C.  Use this information to calculate the specific heat capacity of gold.5.2 J/kg °C65 J/kg °C43.3 J/kg °C130 J/kg °C5What is meant by the specific latent heat of fusion of a substance?The amount of energy released when 1 kilogram of the substance changes from a gas to a liquid (at the same temperature)The amount of energy needed to fuse together two of the particles that make up the substanceThe amount of energy needed to change 1 kilogram of the substance from a solid to a liquid (at the same temperature)The total amount of energy needed to freeze a given amount of the substance6A beaker of (liquid) water has been heated to its boiling point.  Calculate the mass of water which will evaporate when an additional 565 kJ of energy is transferred to the water.  The specific latent heat of vaporisation of water is 2.26 MJ/kg (2,260,000 J/kg).250 kg0.25 kg1276.9 kg0.25 g

A chemist mixes 75.0 g of an unknown substance at 96.5°C with 1,150 g of water at 25.0°C. If the final temperature of the system is 37.1°C, what is the specific heat capacity of the substance? Use 4.184 J / g °C for the specific heat capacity of water.  A. 368 J / g °C  B. 13.1 J / g °C  C. 0.368 J / g °C  D. 0.0112 J / g °C