Pramod goes to a shop to buy some clothes. Shopkeeper shows him 5 shirts, 6 pants and 13 t-shirts. If he selects three clothes at random, then find the probability that, randomly chosen clothes does not contain pant.
Question
Pramod goes to a shop to buy some clothes. Shopkeeper shows him 5 shirts, 6 pants and 13 t-shirts. If he selects three clothes at random, then find the probability that, randomly chosen clothes does not contain pant.
Solution
To solve this problem, we first need to understand the total number of ways Pramod can select three clothes from the given options.
The total number of clothes is 5 shirts + 6 pants + 13 t-shirts = 24 clothes.
The number of ways to select 3 clothes out of 24 is given by the combination formula C(n, r) = n! / [(n-r)!r!], where n is the total number of items, and r is the number of items to choose.
So, the total number of ways to select 3 clothes out of 24 is C(24, 3) = 24! / [(24-3)!3!] = 2024 ways.
Next, we need to find the number of ways to select 3 clothes without a pant. This means we can only choose from the shirts and t-shirts, which total 5 + 13 = 18 clothes.
The number of ways to select 3 clothes out of these 18 is C(18, 3) = 18! / [(18-3)!3!] = 816 ways.
The probability that the randomly chosen clothes do not contain a pant is therefore the number of ways to choose 3 clothes without a pant divided by the total number of ways to choose 3 clothes.
So, the probability = 816 / 2024 = 0.403.
Therefore, the probability that the randomly chosen clothes do not contain a pant is 0.403 or 40.3%.
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