The distance between places A and B is 999 km. An express train leaves place A at 6 am and runs at a speed of 55.5 km/hr. The train stops on the way for 1 hours 20 minutes. It reaches B at?Options1.20 AM6 PM11:00 PM12:00 PM
Question
The distance between places A and B is 999 km. An express train leaves place A at 6 am and runs at a speed of 55.5 km/hr. The train stops on the way for 1 hours 20 minutes. It reaches B at?Options1.20 AM6 PM11:00 PM12:00 PM
Solution
To solve this problem, we need to find out how long the train journey takes, including the time it stops.
Step 1: Calculate the time taken to travel from A to B without considering the stoppage time. The distance between A and B is 999 km and the speed of the train is 55.5 km/hr. So, the time taken to travel from A to B is Distance/Speed = 999 km / 55.5 km/hr = 18 hours.
Step 2: Add the stoppage time to the travel time. The train stops for 1 hour and 20 minutes. Convert this time to hours by dividing the minutes by 60. So, 20 minutes = 20/60 = 0.33 hours. Therefore, the total stoppage time is 1 hour + 0.33 hours = 1.33 hours.
Step 3: Add the travel time and the stoppage time to get the total time taken for the journey. Total time = Travel time + Stoppage time = 18 hours + 1.33 hours = 19.33 hours.
Step 4: Convert the decimal part of the hours to minutes by multiplying by 60. 0.33 hours = 0.33 * 60 = 20 minutes.
So, the total time taken for the journey is 19 hours and 20 minutes.
Step 5: The train leaves place A at 6 am. So, to find out when it reaches B, add the total time taken for the journey to the departure time. 6 am + 19 hours = 1 am next day. Add the 20 minutes to get the exact time. So, the train reaches B at 1:20 am the next day.
Therefore, none of the options provided are correct. The train reaches B at 1:20 am the next day.
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