When 1-bromobutane is treated with sodium acetylide, what products predominate?Select answer from the options below1-hexyne and NaBr1-butene, acetylene, and NaBrNo reaction occurs2-hexyne and NaBr

Sure, let's break down the reaction step by step.

1. Identify the reactants:

   • 1-bromobutane (C4H9Br)
   • Sodium acetylide (NaC≡CH)

2. Understand the nature of the reactants:

   • 1-bromobutane is a primary alkyl halide.
   • Sodium acetylide is a strong nucleophile and a strong base.

3. Predict the type of reaction:

   • Given that sodium acetylide is a strong nucleophile, it will likely undergo a nucleophilic substitution reaction with 1-bromobutane.

4. Mechanism of the reaction:

   • The acetylide ion (C≡C⁻) will attack the carbon atom bonded to the bromine in 1-bromobutane, displacing the bromine atom.
   • This is an SN2 reaction mechanism because 1-bromobutane is a primary alkyl halide, which favors SN2 reactions.

5. Write the reaction:

   • C4H9Br + NaC≡CH → C4H9C≡CH + NaBr

6. Identify the product:

   • The product formed is 1-hexyne (C4H9C≡CH) and sodium bromide (NaBr).

Therefore, the predominant products are 1-hexyne and NaBr.

So, the correct answer is: 1-hexyne and NaBr