A cue ball of weight W is falling with acceleration g/2 downward and speed v. What would be the terminal velocity of this ball as it continues to fall?Select one:a.2vb.vc.v /2d.v
Question
A cue ball of weight W is falling with acceleration g/2 downward and speed v. What would be the terminal velocity of this ball as it continues to fall?Select one:a.2vb.vc.v /2d.v
Solution
The terminal velocity is reached when the force due to gravity is balanced by the drag force acting on the object. In this case, the weight of the cue ball (W) is falling with an acceleration of g/2, which means the drag force is equal to W/2.
The terminal velocity is the speed at which the drag force equals the gravitational force. Since the drag force is proportional to the square of the speed, we can set up the following equation:
W = kv^2
where k is a constant of proportionality.
Given that the cue ball is already falling with speed v when the acceleration is g/2, we can substitute these values into the equation:
W = k(v)^2
Solving for k gives:
k = W / v^2
Substituting this value back into the equation gives:
W = (W / v^2) * v^2
Simplifying this equation gives:
W = W
This means that the terminal velocity of the cue ball is v.
So, the correct answer is d. v.
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