Select the correct answerWhat will be the output of the following Python code?def p(num): if num == 0: return 0 elif num == 1: return 1 else: return p(num-1)+p(num-2)for k in range(0,4): print(p(k),end=" ")OptionsAn exception is thrown 0 1 2 30 1 1 2 30 1 1 2
Question
Select the correct answerWhat will be the output of the following Python code?def p(num): if num == 0: return 0 elif num == 1: return 1 else: return p(num-1)+p(num-2)for k in range(0,4): print(p(k),end=" ")OptionsAn exception is thrown 0 1 2 30 1 1 2 30 1 1 2
Solution
The correct answer is "0 1 1 2".
Here's the step-by-step explanation:
The function p(num) is a recursive function that implements the Fibonacci sequence. The Fibonacci sequence is a series of numbers in which each number is the sum of the two preceding ones, usually starting with 0 and 1.
The for loop in the code is iterating over the range from 0 to 3 (as the upper limit in range() is exclusive). For each iteration, it calls the function p() with the current number and prints the result.
Here's what happens in each iteration:
- For
k = 0, the function returns 0 (according to the firstifcondition in the function). - For
k = 1, the function returns 1 (according to theelifcondition in the function). - For
k = 2, the function callsp(1)andp(0)and returns their sum, which is 1. - For
k = 3, the function callsp(2)andp(1)and returns their sum, which is 2.
So, the output of the code is "0 1 1 2".
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