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Select the correct answerWhat will be the output of the following Python code?def p(num):  if num == 0:    return 0  elif num == 1:    return 1  else:    return p(num-1)+p(num-2)for k in range(0,4):  print(p(k),end=" ")OptionsAn exception is thrown 0 1 2 30 1 1 2 30 1 1 2

Question

Select the correct answerWhat will be the output of the following Python code?def p(num):  if num == 0:    return 0  elif num == 1:    return 1  else:    return p(num-1)+p(num-2)for k in range(0,4):  print(p(k),end=" ")OptionsAn exception is thrown 0 1 2 30 1 1 2 30 1 1 2

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Solution

The correct answer is "0 1 1 2".

Here's the step-by-step explanation:

The function p(num) is a recursive function that implements the Fibonacci sequence. The Fibonacci sequence is a series of numbers in which each number is the sum of the two preceding ones, usually starting with 0 and 1.

The for loop in the code is iterating over the range from 0 to 3 (as the upper limit in range() is exclusive). For each iteration, it calls the function p() with the current number and prints the result.

Here's what happens in each iteration:

  • For k = 0, the function returns 0 (according to the first if condition in the function).
  • For k = 1, the function returns 1 (according to the elif condition in the function).
  • For k = 2, the function calls p(1) and p(0) and returns their sum, which is 1.
  • For k = 3, the function calls p(2) and p(1) and returns their sum, which is 2.

So, the output of the code is "0 1 1 2".

This problem has been solved

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