To solve this problem, we can use the dilution formula:

$$ C_1 V_1 = C_2 V_2 $$

where:
- $ C_1 $ is the concentration of the stock solution (15 M),
- $ V_1 $ is the volume of the stock solution we need to find,
- $ C_2 $ is the concentration of the final solution (2 M),
- $ V_2 $ is the volume of the final solution (750 mL).

Rearranging the formula to solve for $ V_1 $:

$$ V_1 = \frac{C_2 V_2}{C_1} $$

Substituting the given values:

$$ V_1 = \frac{2 \, \text{M} \times 750 \, \text{mL}}{15 \, \text{M}} $$

$$ V_1 = \frac{1500 \, \text{mL}}{15} $$

$$ V_1 = 100 \, \text{mL} $$

So, the volume of the stock solution required is:

100 mL

Question

To solve this problem, we can use the dilution formula:

$$ C_1 V_1 = C_2 V_2 $$

where:
- $ C_1 $ is the concentration of the stock solution (15 M),
- $ V_1 $ is the volume of the stock solution we need to find,
- $ C_2 $ is the concentration of the final solution (2 M),
- $ V_2 $ is the volume of the final solution (750 mL).

Rearranging the formula to solve for $ V_1 $:

$$ V_1 = \frac{C_2 V_2}{C_1} $$

Substituting the given values:

$$ V_1 = \frac{2 \, \text{M} \times 750 \, \text{mL}}{15 \, \text{M}} $$

$$ V_1 = \frac{1500 \, \text{mL}}{15} $$

$$ V_1 = 100 \, \text{mL} $$

So, the volume of the stock solution required is:

100 mL

Knowee AI · Accepted Answer

To solve this problem, we can use the dilution formula:

$$ C_1 V_1 = C_2 V_2 $$

where:
- $ C_1 $ is the concentration of the stock solution (15 M),
- $ V_1 $ is the volume of the stock solution we need to find,
- $ C_2 $ is the concentration of the final solution (2 M),
- $ V_2 $ is the volume of the final solution (750 mL).

Rearranging the formula to solve for $ V_1 $:

$$ V_1 = \frac{C_2 V_2}{C_1} $$

Substituting the given values:

$$ V_1 = \frac{2 \, \text{M} \times 750 \, \text{mL}}{15 \, \text{M}} $$

$$ V_1 = \frac{1500 \, \text{mL}}{15} $$

$$ V_1 = 100 \, \text{mL} $$

So, the volume of the stock solution required is:

100 mL

A lab technician was required to make 750 mL of a 2M solution of hydrochloric acid. They found an 15 M stock solution. What volume of stock solution was required to make the required solution? Question 5 options: 0.1 mL 10 L 100 mL 562 mL 40 mL

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