What does an Open Left membership function imply about the leftmost part of the function? It has a sharp peak It has a gradual slope It extends infinitely to the left None of the above
Question
What does an Open Left membership function imply about the leftmost part of the function? It has a sharp peak It has a gradual slope It extends infinitely to the left None of the above
Solution 1
An Open Left membership function implies that it extends infinitely to the left. This means that the leftmost part of the function does not have a definite end point, but rather continues indefinitely. This is different from a function with a sharp peak or a gradual slope, which have definite shapes and end points. Therefore, the correct answer is "It extends infinitely to the left".
Solution 2
An Open Left membership function implies that it extends infinitely to the left. This means that the leftmost part of the function does not have a definite end point, but rather continues indefinitely. This is different from a function with a sharp peak or a gradual slope, which have definite shapes and end points. Therefore, the correct answer is "It extends infinitely to the left".
Similar Questions
An Open Right membership function is characterized by: An infinite extension to the right It extends infinitely to the left Being symmetric around the peak None of the above
Given an Open Left membership function with a peak at x = 4, if the degree of membership at x = 2 is 1.0, what is the degree of membership at x = 1? 0.2 0.4 1.0 None of the above
The graph of a function g is shown.The x y-coordinate plane is given. A function labeled y = g(x) with 4 parts is graphed.The first part is a curve, enters the window in the second quadrant, goes up and right becoming less steep, crosses the y-axis at approximately y = 2.5, and ends at the open point (2, 3).The second part is a curve begins again at the open point (2, 1), goes up and right becoming less steep, and ends at the open point (5, 2).The third part is the closed approximate point (5, 1.2).The fourth part is a curve, begins at the open point (5, 2) goes down and right becoming more steep, and exits the window in the first quadrant.Use it to state the values (if they exist) of the following:(a) lim x → 2− g(x)(b) lim x → 2+ g(x)(c) lim x → 2 g(x)(d) lim x → 5− g(x)(e) lim x → 5+ g(x)(f) lim x → 5 g(x)SolutionLooking at the graph we see that the values of g(x) approach as x approaches 2 from the left, but they approach as x approaches 2 from the right.Therefore (a) lim x → 2− g(x) = and (b) lim x → 2+ g(x) = .Since the left and right limits are different, we conclude that (c) the limit as x approaches 2 of g(x) does not exist.The graph also shows that (d) lim x → 5− g(x) = and (e) lim x → 5+ g(x) = .This time, the left and right limits are the same and so, by this theorem, we have (f) lim x → 5 g(x) = Despite this fact, notice that g(5) ≠ 2.
Which of the following is a disadvantage of using Open Right membership functions? Lack of expressiveness Difficulty in implementation Limited applicability Potential for uncertainty on the right side None of the above
Consider the functions below.𝑓(𝑥)=𝑥𝑔(𝑥)=15𝑥Which of the following statements describes the graph of function g? A. The graph of g is one-fifth as steep as the graph of f. B. The graph of g is one-fifth of a unit to the left of the graph of f. C. The graph of g is five times steeper than the graph of f. D. The graph of g is one-fifth of a unit to the right of the graph of f.
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