(x, p) = a(x − p)^2 + b(x − p) + c, where a, b, c are constants and a < 0 and ‘p’ is a natural number. It is given that the roots of the equation ax^2 + bx +c = 0 are 3, 4. Then, the value of x at which f(x, 5) attains its maximum value is _______.Choices:- 9 9.5 7.5 5.5
Question
(x, p) = a(x − p)^2 + b(x − p) + c, where a, b, c are constants and a < 0 and ‘p’ is a natural number. It is given that the roots of the equation ax^2 + bx +c = 0 are 3, 4. Then, the value of x at which f(x, 5) attains its maximum value is _______.Choices:- 9 9.5 7.5 5.5
Solution 1
The given equation is in the form of a quadratic equation. The maximum or minimum value of a quadratic equation ax^2 + bx + c is given by -b/2a.
Given that a < 0, the equation will have a maximum value.
The roots of the equation are given as 3 and 4. The sum of the roots of a quadratic equation is given by -b/a and the product of the roots is given by c/a.
So, we have:
3 + 4 = -b/a => -b/a = 7 => b = -7a
and
3*4 = c/a => c/a = 12 => c = 12a
Substituting these values in the equation for the maximum value, we get:
x = -b/2a = -(-7a)/2a = 7/2 = 3.5
But the question asks for the value of x at which f(x, 5) attains its maximum value. The function f(x, 5) is a shift of the original function f(x) by 5 units to the right. Therefore, the maximum value of f(x, 5) will occur at x = 3.5 + 5 = 8.5.
However, this is not one of the given options. There might be a mistake in the problem or in the given options.
Solution 2
The given equation is a quadratic equation in the form of f(x, p) = a(x − p)^2 + b(x − p) + c.
The maximum or minimum value of a quadratic equation ax^2 + bx + c is given by the vertex of the parabola, which is at x = -b/2a.
However, in this case, the equation is shifted by 'p' units, so the maximum value will be at x = p - b/2a.
Given that a < 0, the parabola opens downwards, so it will have a maximum value.
Also, it is given that the roots of the equation ax^2 + bx + c = 0 are 3 and 4. The sum of the roots of a quadratic equation is given by -b/a and the product of the roots is given by c/a.
So, we have -b/a = 3 + 4 = 7 and c/a = 3*4 = 12.
From -b/a = 7, we get b = -7a.
Substituting b = -7a in the equation for the maximum value, we get x = p - (-7a)/2a = p + 7/2.
Given that p = 5, we substitute p in the above equation to get x = 5 + 7/2 = 8.5.
So, the value of x at which f(x, 5) attains its maximum value is 8.5. However, this is not one of the given choices. There might be a mistake in the problem or the choices.
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