Which of the following is a correct factorization of this trinomial?-3x2 - 10x - 8A.-(x + 4)(x - 3)B.-(3x + 4)(x + 2)C.-3(x + 4)(x + 2)D.(-3x + 4)(x - 2)SUBMITarrow_backPREVIOUS
Question
Which of the following is a correct factorization of this trinomial?-3x2 - 10x - 8A.-(x + 4)(x - 3)B.-(3x + 4)(x + 2)C.-3(x + 4)(x + 2)D.(-3x + 4)(x - 2)SUBMITarrow_backPREVIOUS
Solution
The correct factorization of the trinomial -3x^2 - 10x - 8 is C. -3(x + 4)(x + 2).
Here's how you can factorize it:
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First, look for two numbers that multiply to -24 (which is the product of -3 and -8) and add up to -10. Those numbers are -6 and 4.
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Rewrite the middle term of the trinomial as the sum of the terms -6x and 4x. So, -3x^2 - 10x - 8 becomes -3x^2 - 6x + 4x - 8.
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Factor by grouping. The first two terms can be grouped together, and the last two terms can be grouped together. This gives us -3x(x + 2) + 4(x + 2).
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Notice that (x + 2) is a common factor. So, you can factor that out to get (x + 2)(-3x + 4).
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However, to match the answer choices given, we can rewrite -3x + 4 as -1*(3x - 4), which gives us -1*(3x - 4)(x + 2).
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So, the correct factorization is -3(x + 4)(x + 2).
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