2. What is the term a8 of the sequence {an} if an equalsa) 2n−1? b) 7? c) 1 + (−1)n? d) −(−2)n?
Question
- What is the term a8 of the sequence {an} if an equalsa) 2n−1? b) 7? c) 1 + (−1)n? d) −(−2)n?
Solution
a) Para encontrar el término a8 de la secuencia {an} donde an = 2n - 1, sustituimos n por 8:
a8 = 2(8) - 1 a8 = 16 - 1 a8 = 15
b) Si an = 7, entonces todos los términos de la secuencia son 7, incluyendo a8:
a8 = 7
c) Para encontrar el término a8 de la secuencia {an} donde an = 1 + (−1)n, sustituimos n por 8:
a8 = 1 + (−1)^8 a8 = 1 + 1
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